C# – Dynamic Type

By | 24/02/2021

In this post, we will see what a Dynamic Type is and how to use it.

Dynamic Type was introduced in C# 4.0 and it avoids compile-time type checking.
It escapes type checking at compile-time and it resolves type a run time.
A dynamic type variable is defined using the dynamic keyword.
Let see some examples:

DEFINING A DYNAMIC TYPE:

static void Main(string[] args)
{
    // we define the value1 as a string     
    dynamic value1 = "hello";
    Console.WriteLine($"The first variable is {value1} and it is a {value1.GetType().ToString()}");
   
    // now, we save an integer
    value1 = 3;
    Console.WriteLine($"The first variable is {value1} and it is a {value1.GetType().ToString()}");
            
    // finally, we save a boolean
    value1 = false;
    Console.WriteLine($"The first variable is {value1} and it is a {value1.GetType().ToString()}");
}



If we run this code, this will be the result:

PASSING A DYNAMIC TYPE IN A FUNCTION:

static void Main(string[] args)
{
    // we define the value1 as a string
    dynamic value1 = "hello";
    Console.WriteLine($"The variable is {value1} and it is a {CheckType(value1)}");
    // now, we save an integer
    value1 = 3;
    Console.WriteLine($"The variable is {value1} and it is a {CheckType(value1)}");
    // finally, we save a boolean
    value1 = false;
    Console.WriteLine($"The variable is {value1} and it is a {CheckType(value1)}");
}

private static string CheckType(dynamic inputValue)
{
    var valueType = inputValue.GetType();

    if (valueType.Equals(typeof(int)))
    {
        return "Integer";
    }
    else if (valueType.Equals(typeof(string)))
    {
        return "string";
    }
    else
    {
        return "bool";
    }
}



If we run the code, this will be the result:

USING A DYNAMIC TYPE AS RETURN TYPE:

static void Main(string[] args)
{
    // we define the value1 and value2 as string
    dynamic value1 = "hello";
    dynamic value2 = "world";
    Console.WriteLine($"{Add(value1, value2)}");

    // we define the value1 and value2 as integer
    value1 = 5;
    value2 = 6;
    Console.WriteLine($"{Add(value1, value2)}");

    // we define the value1 and value2 as decimal
    value1 = 12.6;
    value2 = 18.1;
    Console.WriteLine($"{Add(value1, value2)}");
}

private static dynamic Add(dynamic val1, dynamic val2)
{
    dynamic result = val1 + val2;
    return result;
}



If we run the code, this will be the result:



Category: C# Tags:

Leave a Reply

Your email address will not be published. Required fields are marked *